GSPk9 FcapmdtNS?[ Ag[g[g[Hg[8g[(g[g[g`g[(g[ _[_[_[W[ _[ _[t_[~CBtHM  B '[D'['['[l'['['['D'[ '['[@*DB tZ_UR CCDK dVV`DD t *nl u` olCTHu_U$Berzsenyi Triple Circle Concurrency.~t0W ho6do xd01h _00C pu_Ul uRa =~t1W ho6do xd01h _00C pu_Ul uRb =~t2W ho6do xd01h _00C pu_Ul uRc =~t4 }CKLtfCPV 9 8 r_^[]D$PqDatatz8  BZtLN$UR8PMMEuEjj;j%}uuRadiit4 With the Radii chosen symmetrically as below, each circle that is tangential to two sides of the triangle also intersects the other two circles at a single point. tGS j|V AVW9W~CB@*DB? tG_V( k 9 8 r_^[]D$Pq{{{{B@*DB`DD? tM_t(h lV g[G[?D2/  `DD~CB?tF A= oop AW[X/ m{!:A}CAB = A =  tM B=   E $op B>m{!:A}CAB = 36 m{!:A}ABC = B =  tF C= (DBDC(g[4SCDC>m{!:A}ABC = 83g[ m{!:A}BCA = C =  t 5d  md~CB@*DB?tpRY n@*DB`DD?tQR.Y o(o`0DC@C`DD~CB?tg2 a= am{!:A}BCA = 61 m {S:BC} = a =  t3gK b= bm {S:BC} = 6.19 cm m {S:CA} = b =  tLgd3 c= Commanc1a>m {S:CA} = 10.47 cm m {S:AB} = c =  Ct5'D m7 L2{!:*}sin{(:A}{!:*}sin{(:B}{!:*}sin{(:C} + sin{(:A} + sin{(:B} + sin{(:C} = :2*sin[A] *sin[B] *sin[C] + sin[A] + sin[B] + sin[C] = 888888tmRY p{*_D@C@aD`LD?t P<u quu$uu uHupuuiLuLuuuYuD0D+ߏC 1!tLm R(a)P8 L <'lAR{l:a}< << OD}-C`Bx{O-,03tK R(b)00S4T"TR{l:b}3"/OKD.,C`B8Wu ?24t6 R(c)Lɿ*OP(>XL:ER{l:c}ʿmOP((OP b%D+ߏC`B\G>x{15t9> N DC 86"ArialGM47M