GSPkV F@1capm2t Qy .Drag blue points to resize the original figuret\a Drag to resize?'?o8jp Pq n[t CC tumzr BCd + J'ALCˍC tC:\ AJ'NCtUBN,T4Y<oZhqNDC tNSGN AIsbB@DGNCѹ& GNe$ GNJC BGNBC tV[ AHGNDGNDHGNpD'NpD'N"D@gNCC t8=  AGGN@D !CCLGN<N@Dg!vvvvg!vvvvVCC t E/ EDrag Points along the red lines to see their inverted transformationst @ c19 wd@d,j  c14ALCˍCBF%5?F%5?t!A afDESKTOP\SKETCH~1\INVERS~2\D-ANN~1.GSPBCDC?t!6 m23 Radius {!:C}BCDrag to resize = "Radius(Circle BCDrag to resize) = tY?  BK'7CC  t m20 Radius {!:C}BCDrag to resize = "Radius(Circle BCDrag to resize) = tyf m17ffffff"""33̙ Radius {!:C}BCDrag to resize = "Radius(Circle BCDrag to resize) = t%:C2 m14|٠>V|CxC:F>CC| ?CCI?< Radius {!:C}BCDrag to resize = "Radius(Circle BCDrag to resize) = t>N ah NoZ@NNP$nCBC`D? t> agpmSCBSCD? t |  m22BCBK = Distance(BC to BK) =  ttl" awL LL2DLLRadius(CircALCˍC'7CC?t  ALwd} CC  t-- AKXNXNdNpN6Y$NF4N N:4&4 N64*4(NNSCC  t7^ m24 &{D:{(:Radius {!:C}BCBD}{u:2}}{BCBK} = +Radius(Circle BCBD)^2/Distance(BC to BK) =   t aithe associated Word File to se how Inversion Theory can be used to dSCCCC?t'? c13NHNddSCC,CF%5?F%5?tmr +BC'd + J'~CCˍC t    BEkC C iCi_C t   AR(YFYY>YRH YH@YiYYYY6YHSCC tY  AQYP$nY@YhYYYY YSCC tNSe le AMN, the radii of the internal circles to CC t3+ c23ALCˍC܇BF%5?F%5?t|$:Fq m13|٠> EC%CF>ICFC| ?ZCCCBCBE = Distance(BC to BE) =  t>zr atjaChC  (wd(wdALCˍCiCi_C?tidI@ c14CCBF%5?F%5?t  BL"CC  t;bwd m15 &{D:{(:Radius {!:C}BCBD}{u:2}}{BCBE} = +Radius(Circle BCBD)^2/Distance(BC to BE) = !tumzrN AOIALCˍC #tN ANSCC #t4I Move Circle of Inversionp Pq n[t &'tDo( ?BL$(  $tmr +BC'd + J'1CˍC % t7! aj_NH_ND_N WNWNWNONGpWN`WN\ WN WN WN WN?NtWN7NSCCALCˍC?&tLD c20d!DC3D,C wdwd!DC 3D\C4dW0 dALCˍC,BF%5?F%5?*t~1.G  APERS~2\D-asec~1.gspC:\WINDOWS\DESKTOP\SCC +taGfLC  BFDCdCEDCdj`DTd\$EDCp wdO\DC( wdDCLC ", t al__l_4____T_ ___d__, _ _ _T SCCCC?-t> akm%C2%CC *D? -tr0))aY@ c15?LNYCCBF%5?F%5?-&t?Do  BG?gh?g0?g?g?g ?gX ?gH ? ?g ?g?g?g7g4?g$?g/gX?gJDdC 1't( ?BFDCdCEDCdj`DTd\$EDCp wdO\DC( wdD.("!%*,.tN S'N AU GNGN 'Z(NN 'N't'N,'N<'N,'N( 'N 'N 'NNd'NC JC /t  ATP WYCC 01t.3  ASYYz$Q4YYddC0(C 01tc}xg m16 g@ g g| g g , q q0g?g<gqHBCBG = Distance(BC to BG) = 2 tt!rV au pre  to ld a,$Y_oZALCˍCJDdC?2 t-=e mo aootice that this is only one poitioning of the Circle of Inversion anC0(CSCC?6t[I{@ c16 C JCx1CF%5?F%5?4t$ oh m18 &{D:{(:Radius {!:C}BCBD}{u:2}}{BCBG} = +Radius(Circle BCBD)^2/Distance(BC to BG) = 7tN3S8 AX dCC 9t|Squa AWYtrsion Example (): Find the Radius of the enclosed, sC?/C :1t;@ AVs the geometry of the Inverted(Red) Image.$Y@CxC :1tmr +BC'd + J'CˍC ;t@ c17 Inversionsd:mN @CC0BF%5?F%5?<6 t anSCCC?/C?= tP amSCC@CxC?>t0( c21ALCˍC4BF%5?F%5??te! asDaCiC@~D?A=tBG AZ Drag'?'?o8jp Rq T)C8C @tLQ AY%d9 7 Move J->ZHC C @tW\  BHSCLC 8C tp>3 aqersionp Rq Rt,\C0(CT)C8C?E6 t- ap j! vaCCr5H>:4CCwAC0(CHC C?F6't6( ?BHG(1287;?CGt>' ar4zCfCZC]C?IFtbg BAC,C KDtE3z@ c183.39 cmC,C8AF%5?F%5?LFtDI  BIHCC Mtbg  BB h# @Radius Drag = CC  Mtv m19BCBI = Distance(BC to BI) = N tblz avALCˍCHCC?Nt Hoh m21 &{D:{(:Radius {!:C}BCBD}{u:2}}{BCBI} = +Radius(Circle BCBD)^2/Distance(BC to BI) = Ptmr +BC'd + J'ICˍC Rt  c22ALCˍCBF%5?F%5?StGL  BJCp C QT't)!( ?BJU(MNQPRSTU"ArialoZ0q